MachineSex/tests/test_llm.py
Giorgio Gilestro 5a23ddaf2a Phase 3: LLM-tier speciation + multi-seed firm-up of the recombination claims
llm_speciation (new kind; src/llm/speciation.py): E13 in LLM weights.
LoRA children share the frozen base's coordinates, so merge failure is
functional by construction. CONFLICT (ambiguous sort prompts learned
under opposite conventions — the BDM structure): function-specific
hybrid breakdown — merged coherence 0.02-0.08 falls below BOTH parents
(~0.2) on the conflicted function; and in the de-confounded `add` design
(private budget fixed, conflict added on top; 3 seeds after a
single-seed pilot showed one anomalous point) the merge's private-family
accuracy shows NO trend with conflict — the damage is surgical, not
global. DURATION (over-trained disjoint specialists, 1->12 epochs): the
merge improves (0.84->0.94) and stays above the best parent — the MLP
"no emergent isolation" null generalises; relevant to the
expert-training-duration report (2607.11997), with the epistasis
prediction left to the decisive experiment.

Multi-seed firm-up (seeds threaded into specialist caches; `seeds:` list
support in the runner; fixed test sets): all three recombination claims
hold with CIs — merges beat every specialist (5 seeds, ties
0.647±0.027 > best spec 0.592±0.009; worst-family 0.28 vs <=0.16); union
0.274±0.026 > fusion 0.174±0.102 on hard (3 seeds); directed 0.221±0.026
> soup. NEW finding: fusion is seed-FRAGILE where headroom exists
(CI ±0.10) while routing/directed selection are stable (±0.026) — the
union/selection operators win on reliability, not just mean.

Figures (llm_speciation 3-panel; llm_seeds 3-panel with 95% CI), READMEs,
+1 convention test (150 green), make llm-speciation / llm-seeds targets.

Co-Authored-By: Claude Fable 5 <noreply@anthropic.com>
Claude-Session: https://claude.ai/code/session_01BkRLcc18rwT2Lysu6PbG7v
2026-09-06 15:39:15 +01:00

128 lines
6.7 KiB
Python

"""LLM-prototype tests — the pure, always-runnable parts (task generation + verifier).
The model/LoRA/merge path is heavy (downloads a base model, trains on a GPU) and is validated by the
experiment run itself, not in CI. What *is* unit-testable — and worth locking, since it is the
prototype's "reality that says no" — is that tasks are well-formed and the exact-match verifier
accepts correct answers (including verbose model phrasings) and rejects wrong ones.
"""
from __future__ import annotations
import numpy as np
from llm.directed import sample_merge_weights, select_winners
from llm.moe import learned_routes
from llm.tasks import FAMILIES, make_tasks, verify
def test_make_tasks_wellformed_and_deterministic():
for fam in FAMILIES:
tasks = make_tasks(fam, 20, seed=0)
assert len(tasks) == 20 and all(t.family == fam for t in tasks)
assert all(t.prompt and t.answer for t in tasks)
a = make_tasks("arith", 10, seed=3)
b = make_tasks("arith", 10, seed=3)
assert [t.answer for t in a] == [t.answer for t in b] # deterministic in the seed
def test_hard_tasks_wellformed_verifiable_and_distinct():
# The hard variant must stay well-formed, self-verifying (canonical answer passes its own verifier),
# and genuinely different from the easy variant (harder content, same family labels + answer format).
for fam in FAMILIES:
hard = make_tasks(fam, 30, seed=7, hard=True)
assert len(hard) == 30 and all(t.family == fam for t in hard)
assert all(t.prompt and t.answer for t in hard)
assert all(verify(t.answer, t) for t in hard) # canonical answers verify
easy = make_tasks(fam, 30, seed=7, hard=False)
assert [t.prompt for t in hard] != [t.prompt for t in easy] # hard != easy
# a Caesar-cipher answer is a real transform of the input (not the identity)
caesars = [t for t in make_tasks("strings", 60, seed=2, hard=True) if "Caesar" in t.prompt]
assert caesars and any(t.answer not in t.prompt for t in caesars)
def test_verifier_accepts_correct_including_verbose():
tasks = make_tasks("lists", 40, seed=1) + make_tasks("arith", 40, seed=2)
assert all(verify(t.answer, t) for t in tasks) # the canonical answer verifies
# a verbose but correct model phrasing still verifies (the verifier extracts the answer)
num_task = next(t for t in tasks if t.family == "arith")
assert verify(f"The answer is {num_task.answer}.", num_task)
list_task = next(t for t in tasks if t.family == "lists" and t.answer.startswith("["))
assert verify(f"Here you go: {list_task.answer}", list_task)
def test_verifier_rejects_wrong():
t = make_tasks("arith", 1, seed=5)[0]
wrong = str(int(t.answer) + 1) if t.answer.lstrip("-").isdigit() else "zzz"
assert not verify(wrong, t)
lt = next(x for x in make_tasks("lists", 30, seed=6) if x.answer.startswith("["))
assert not verify("[9, 9, 9]", lt) or lt.answer == "[9, 9, 9]"
def test_learned_router_assigns_nearest_centroid():
# Three well-separated families in a 4-D "embedding" space; the nearest-centroid router
# (the MoE expert-selection gene) must route each test prompt to its own family's specialist.
rng = np.random.default_rng(0)
fams = ["lists", "strings", "arith"]
anchors = {"lists": [5, 0, 0, 0], "strings": [0, 5, 0, 0], "arith": [0, 0, 5, 0]}
train_emb = np.array([anchors[f] for f in fams for _ in range(8)], dtype=float)
train_emb += rng.normal(scale=0.1, size=train_emb.shape)
train_fam = np.array([f for f in fams for _ in range(8)])
test_fam = np.array(["arith", "lists", "strings", "arith"])
test_emb = np.array([anchors[f] for f in test_fam], dtype=float) + rng.normal(scale=0.1, size=(4, 4))
routes = learned_routes(train_emb, train_fam, test_emb, fams)
assert [fams[r] for r in routes] == list(test_fam) # each routed to its own family
def test_learned_router_is_cosine_scale_invariant():
# Cosine routing must ignore prompt-embedding magnitude (long vs short prompts): a test point on a
# family's ray routes there regardless of its norm.
fams = ["a", "b"]
train_emb = np.array([[1.0, 0.0], [1.0, 0.0], [0.0, 1.0], [0.0, 1.0]])
train_fam = np.array(["a", "a", "b", "b"])
test_emb = np.array([[10.0, 0.0], [0.0, 0.01]]) # very different magnitudes
routes = learned_routes(train_emb, train_fam, test_emb, fams)
assert [fams[r] for r in routes] == ["a", "b"]
def test_merge_weights_population_pins_baselines_and_diversifies():
# The offspring population must contain the two canonical baselines (uniform soup, unit task-arith)
# and be diverse + reproducible for the rest.
rng = np.random.default_rng(0)
w = sample_merge_weights(3, 16, rng)
assert w.shape == (16, 3)
assert np.allclose(w[0], 1 / 3) # candidate 0 = uniform soup
assert np.allclose(w[1], 1.0) # candidate 1 = task arithmetic
assert np.unique(w[2:].round(3), axis=0).shape[0] > 5 # the random offspring are diverse
assert np.allclose(sample_merge_weights(3, 16, np.random.default_rng(0)), w) # deterministic
def test_select_winners_picks_argmax_per_objective():
val_overall = np.array([0.5, 0.9, 0.7])
val_worst = np.array([0.4, 0.1, 0.6]) # a different candidate is most balanced
w = select_winners(val_overall, val_worst)
assert w == {"overall": 1, "balanced": 2}
def test_merge_weights_requires_two_candidates():
import pytest
with pytest.raises(ValueError):
sample_merge_weights(3, 1, np.random.default_rng(0))
def test_convention_tasks_conflict_only_between_conventions():
# The BDM structure of llm_speciation: identical prompts, each convention internally consistent
# and verifiable, the two conventions contradictory on (almost) every prompt.
from llm.speciation import make_convention_tasks
from llm.tasks import verify
asc = make_convention_tasks(20, seed=5, convention="asc")
desc = make_convention_tasks(20, seed=5, convention="desc")
assert [a.prompt for a in asc] == [d.prompt for d in desc] # same inputs, graded two ways
assert all(verify(a.answer, a) for a in asc) # each convention self-consistent
assert all(verify(d.answer, d) for d in desc)
conflicting = sum(a.answer != d.answer for a, d in zip(asc, desc))
assert conflicting >= 18 # contradictory unless already sorted
assert all(not verify(a.answer, d) for a, d in zip(asc, desc) if a.answer != d.answer)
# deterministic: prompts and answers are a pure function of (seed, convention)
again = make_convention_tasks(20, seed=5, convention="asc")
assert [t.answer for t in again] == [t.answer for t in asc]